In the LDL calculation example, triglycerides were 200 mg/dL. What is TG divided by 5?

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Study for the Ciulla Clinical Chemistry Test. Enhance your knowledge with flashcards and multiple-choice questions. Prepare for the exam with comprehensive study materials and detailed explanations for each question.

Multiple Choice

In the LDL calculation example, triglycerides were 200 mg/dL. What is TG divided by 5?

Explanation:
TG divided by 5 gives the estimate of VLDL cholesterol in the Friedewald equation. In fasting plasma, the amount of cholesterol carried by VLDL is roughly one-fifth of the triglyceride level, so VLDL-C ≈ TG/5. With triglycerides at 200 mg/dL, TG/5 equals 40 mg/dL. This 40 mg/dL is the VLDL-C term used in the LDL calculation (LDL-C = TC − HDL-C − VLDL-C). The value is valid here because triglycerides are under 400 mg/dL and the patient is fasting.

TG divided by 5 gives the estimate of VLDL cholesterol in the Friedewald equation. In fasting plasma, the amount of cholesterol carried by VLDL is roughly one-fifth of the triglyceride level, so VLDL-C ≈ TG/5. With triglycerides at 200 mg/dL, TG/5 equals 40 mg/dL. This 40 mg/dL is the VLDL-C term used in the LDL calculation (LDL-C = TC − HDL-C − VLDL-C). The value is valid here because triglycerides are under 400 mg/dL and the patient is fasting.

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